# Digital Encoder or Binary Encoder

on 24/2/2012 & Updated on 31/7/2018Suppose we have to design an encoder which will encode 10 characters (from 0 to 9). The encoded form of each character would be 4 bit binary equivalent. Then the encoder will have 10 numbers of input lines and each for one character. There will be four output lines to represent 4 bit encoded form of each input character.

__Related pages__

Similarly for encoding M numbers of characters in N bit format, we need M input N output **digital encoder**.
In encoder normally, the input of which encoding to be done, is made high, other all inputs remain low at that time. That means a digital encoder works on active high input.
To understand about a **digital encoder** let us design the above decimal to binary encodes. The truth table for 10 inputs 4 output encoder would be,

From truth table it is found, that output A would be high at D_{8}, D_{9}.
So, it can be written
From above 4 equations the logic circuit drawn as follows,
Figure:3
This circuit can also be considered as Decimal to BCD encoder.

## Octal to Binary Encoder

The octal numbers system has bas of 8. Hence the number of digits used in octal system is 8 and the octal digits are 0 to 7. Hence, there will be eight input line in a basic**Octal to binary encoder**. As binary equivalent of numbers 0 to 7 can be represented by only three binary bits, there will be three output lines to represent bits of binary equivalent of octal number. The truth table logical relations between inputs and outputs and corresponding logic circuit are shown as follows,

Octal Digit | Binary Equivalent | ||

A | B | C | |

D_{0} → 0 | 0 | 0 | 0 |

D_{1} → 1 | 0 | 0 | 1 |

D_{2} → 2 | 0 | 1 | 0 |

D_{3} → 3 | 0 | 1 | 1 |

D_{4} → 4 | 1 | 0 | 0 |

D_{5} → 5 | 1 | 0 | 1 |

D_{6} → 6 | 1 | 1 | 0 |

D_{7} → 7 | 1 | 1 | 1 |

Rating = 3 & Total votes = 2