Long Transmission Lineon 24/2/2012 & Updated on Saturday 28th of April 2018 at 12:52:16 PM
The reason being that, the effective circuit length in this case is much higher than what it was for the former models (long and medium line) and, thus ruling out the approximations considered there like.
- Ignoring the shunt admittance of the network, like in a small transmission line model.
- Considering the circuit impedance and admittance to be lumped and concentrated at a point as was the case for the medium line model.
Here a line of length l > 250km is supplied with a sending end voltage and current of VS and IS respectively, where as the VR and IR are the values of voltage and current obtained from the receiving end. Lets us now consider an element of infinitely small length Δx at a distance x from the receiving end as shown in the figure where. V = value of voltage just before entering the element Δx. I = value of current just before entering the element Δx. V+ΔV = voltage leaving the element Δx. I+ΔI = current leaving the element Δx. ΔV = voltage drop across element Δx. zΔx = series impedence of element Δx yΔx = shunt admittance of element Δx Where, Z = z l and Y = y l are the values of total impedance and admittance of the long transmission line.
Therefore, the voltage drop across the infinitely small element Δx is given by Now to determine the current ΔI, we apply KCL to node A. Since the term ΔV yΔx is the product of 2 infinitely small values, we can ignore it for the sake of easier calculation. Therefore, we can write
Now derivating both sides of eq (1) w.r.t x, Now substituting from equation (2) The solution of the above second order differential equation is given by. Derivating equation (4) w.r.to x. Now comparing equation (1) with equation (5)
Now to go further let us define the characteristic impedance Zc and propagation constant δ of a long transmission line as Then the voltage and current equation can be expressed in terms of characteristic impedance and propagation constant as Now at x=0, V= VR and I= Ir. Substituting these conditions to equation (7) and (8) respectively. Solving equation (9) and (10), We get values of A1 and A2 as, Now applying another extreme condition at x = l, we have V = VS and I = IS. Now to determine VS and IS we substitute x by l and put the values of A1 and A2 in equation (7) and (8) we get By trigonometric and exponential operators we know Therefore, equation (11) and (12) can be re-written as Thus comparing with the general circuit parameters equation, we get the ABCD parameters of a long transmission line as,
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