# Hysteresis Eddy Current Iron or Core Losses and Copper Loss in Transformer

on 24/2/2012 & Updated on 22/7/2018## Losses in Transformer

As the electrical transformer is a static device, mechanical loss in transformer normally does not come into picture. We generally consider only electrical**losses in transformer**. Loss in any machine is broadly defined as difference between input power and output power. When input power is supplied to the primary of transformer, some portion of that power is used to compensate

**core losses in transformer**i.e.

**Hysteresis loss in transformer**and

**Eddy current loss in transformer**core and some portion of the input power is lost as I

^{2}R loss and dissipated as heat in the primary and secondary windings, because these windings have some internal resistance in them. The first one is called core loss or

**iron loss in transformer**and the later is known as ohmic loss or

**copper loss in transformer**. Another loss occurs in transformer, known as Stray Loss, due to Stray fluxes link with the mechanical structure and winding conductors.

## Copper Loss in Transformer

Copper loss is I^{2}R loss, in primary side it is I

_{1}

^{2}R

_{1}and in secondary side it is I

_{2}

^{2}R

_{2}loss, where I

_{1}and I

_{2}are primary and secondary current of transformer and R

_{1}and R

_{2}are resistances of primary and secondary winding. As the both primary & secondary currents depend upon load of transformer,

**copper loss in transformer**vary with load.

__Related pages__

## Core Losses in Transformer

Hysteresis loss and eddy current loss, both depend upon magnetic properties of the materials used to construct the core of transformer and its design. So these**losses in transformer**are fixed and do not depend upon the load current. So

**core losses in transformer**which is alternatively known as

**iron loss in transformer**can be considered as constant for all range of load.

**Hysteresis loss in transformer**is denoted as,

**Eddy current loss in transformer**is denoted as, Where, K

_{h}= Hysteresis constant. K

_{e}= Eddy current constant. K

_{f}= form constant.

Copper loss can simply be denoted as,

_{L}

^{2}R

_{2}′ + Stray loss

_{L}= I

_{2}= load of transformer, and R

_{2}′ is the resistance of transformer referred to secondary. Now we will discuss Hysteresis loss and Eddy current loss in little bit more details for better understanding the topic of losses in transformers.

## Hysteresis Loss in Transformer

Hysteresis loss in transformers can be explained in different ways. We will discuss two of them, one is the physical explanation, and the other is the mathematical explanation.### Physical Explanation of Hysteresis Loss

The magnetic core of transformer is made of ′Cold Rolled Grain Oriented Silicon Steel′. Steel is very good ferromagnetic material. This kind of materials is very sensitive to be magnetized. That means, whenever magnetic flux would pass through, it will behave like magnet. Ferromagnetic substances have numbers of domains in their structure. Domains are very small regions in the material structure, where all the dipoles are paralleled to the same direction. In other words, the domains are like small permanent magnets situated randomly in the structure of the substance. These domains are arranged inside the material structure in such a random manner, that net resultant magnetic field of the said material is zero. Whenever external magnetic field or mmf is applied to that substance, these randomly directed domains get arranged themselves in parallel to the axis of applied mmf. After removing this external mmf, maximum numbers of domains again come to random positions, but some of them still remain in their changed position. Because of these unchanged domains, the substance becomes slightly magnetized permanently. This magnetism is called "Spontaneous Magnetism". To neutralize this magnetism, some opposite mmf is required to be applied. The magnetomotive force or mmf applied in the transformer core is alternating. For every cycle due to this domain reversal, there will be extra work done. For this reason, there will be a consumption of electrical energy which is known as Hysteresis loss of transformer.### Mathematical Explanation of Hysteresis Loss in Transformer

#### Determination of Hysteresis Loss

Consider a ring of a ferromagnetic specimen of circumference L meter, cross-sectional area a m^{2}and N turns of insulated wire as shown in the picture beside,

Let us consider, the current flowing through the coil is I amp, Magnetizing force, Let, the flux density at this instant is B, Therefore, total flux through the ring, Φ = BXa Wb As the current flowing through the solenoid is alternating, the flux produced in the iron ring is also alternating in nature, so the emf (e′) induced will be expressed as, According to Lenz,s law this induced emf will oppose the flow of current, therefore, in order to maintain the current I in the coil, the source must supply an equal and opposite emf. Hence applied emf, Energy consumed in short time dt, during which the flux density has changed, Thus, total work done or energy consumed during one complete cycle of magnetism is, Now aL is the volume of the ring and H.dB is the area of the elementary strip of B - H curve shown in the figure above, Therefore, Energy consumed per cycle = volume of the ring × area of hysteresis loop. In the case of transformer, this ring can be considered as magnetic core of transformer. Hence, the work done is nothing but the electrical energy loss in transformer core and this is known as hysteresis loss in transformer.

## What is Eddy Current Loss?

In transformer, we supply alternating current in the primary, this alternating current produces alternating magnetizing flux in the core and as this flux links with secondary winding, there will be induced voltage in secondary, resulting current to flow through the load connected with it. Some of the alternating fluxes of transformer; may also link with other conducting parts like steel core or iron body of transformer etc. As alternating flux links with these parts of transformer, there would be a locally induced emf. Due to these emfs, there would be currents which will circulate locally at that parts of the transformer. These circulating current will not contribute in output of the transformer and dissipated as heat. This type of energy loss is called eddy current loss of transformer. This was a broad and simple explanation of eddy current loss. The detail explanation of this loss is not in the scope of discussion in that chapter.Rating = 4.03 & Total votes = 27