The stability analysis of a feedback control system is based on identifying the location of the roots of the characteristic equation on s-plane. The system is stable if the roots lie on left hand side of s-plane. Relative stability of a system can be determined by using frequency response methods like Nyquist plot and Bode plot. Nyquist criterion is used to identify the presence of roots of a characteristic equation in a specified region of s-plane. To understand Nyquist plot we need to know about some of the terminologies.
Contour : Closed path in a complex plane is called contour.
Nyquist path or Nyquist contourThe Nyquist contour is a closed contour in the s-plane which completely encloses the entire right hand half of s-plane. In order to enclose the complete RHS of s-plane a large semicircle path is drawn with diameter along jω axis and centre at origin. The radius of the semicircle is treated as Nyquist Encirclement.
Nyquist EncirclementA point is said to be encircled by a contour if it is found inside the contour.
Nyquist MappingThe process by which a point in s-plane is transformed into a point in F(s) plane is called mapping and F(s) is called mapping function.
Steps of drawing the Nyquist path
- Step 1 - Check for the poles of G(s) H(s) of jω axis including that at origin.
- Step 2 - Select the proper Nyquist contour – a) Include the entire right half of s-plane by drawing a semicircle of radius R with R tends to infinity.
- Step 3 - Identify the various segments on the contour with reference to Nyquist path
- Step 4 - Perform the mapping segment by segment by substituting the equation for respective segment in the mapping function. Basically we have to sketch the polar plots of the respective segment.
- Step 5 - Mapping of the segments are usually mirror images of mapping of respective path of +ve imaginary axis.
- Step 6 - The semicircular path which covers the right half of s plane generally maps into a point in G(s) H(s) plane.
- Step 7- Interconnect all the mapping of different segments to yield the required Nyquist diagram.
- Step 8 - Note the number of clockwise encirclement about (-1, 0) and decide stability by N = Z – P
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is the Closed loop transfer function (C.L.T.F) N(s) = 0 is the open loop zero and D(s) is the open loop pole From stability point of view no closed loop poles should lie in the RH side of s-plane. Characteristics equation 1 + G(s) H(s) = 0 denotes closed loop poles . Now as 1 + G(s) H(s) = 0 hence q(s) should also be zero. Therefore , from the stability point of view zeroes of q(s) should not lie in RHP of s-plane. To define the stability entire RHP (Right Hand Plane) is considered. We assume a semicircle which encloses all points in the RHP by considering the radius of the semicircle R tends to infinity. [R → ∞].
The first step to understand the application of Nyquist criterion in relation for determination of stability of control systems is mapping from s-plane to G(s) H(s) - plane. s is considered as independent complex variable and corresponding value of G(s) H(s) being the dependent variable plotted in another complex plane called G(s) H(s) - plane. Thus for every point in s-plane there exists a corresponding point in G(s) H(s) - plane. During the process of mapping the independent variable s is varied along a specified path in s - plane and the corresponding points in G(s)H(s) plane are joined. This completes the process of mapping from s-plane to G(s)H(s) - plane. Nyquist stability criterion says that N = Z - P. Where, N is the total no. of encirclement about the origin, P is the total no. of poles and Z is the total no. of zeroes. Case 1 :- N = 0 (no encirclement), so Z = P = 0 and Z = P If N = 0, P must be zero therefore system is stable. Case 2 :- N > 0 (clockwise encirclement), so P = 0, Z ≠0 and Z > P For both cases system is unstable. Case 3 :- N < 0 (counter clockwise encirclement), so Z = 0, P ≠0 and P > Z System is stable.
|S||SRINIVAS commented on 09/04/2018|
It will be easy if you have given an example problem.