Types of JFET | N Channel JFET | P Channel JFETPublished on 24/2/2012 and last updated on 15/11/2018
n-channel JFETThe schematic of an n-channel JFET along with its circuit symbol is shown in Figure 1. From the layered structure shown by Figure 1a, it is clear that the n-channel JFET has its major portion made of n-type semiconductor. The mutually-opposite two faces of this bulk material from the source and the drain terminals. Further, it is also seen that there are two relatively-small p-regions embedded into this substrate which are internally joined together to form the gate terminal. Thus, here, the source and the drain terminals are of n-type while the gate is of p-type. Due to this, two pn junctions will be formed within the device, whose analysis reveals the mode in which the JFET works. Further the circuit symbol shown by Figure 1b has an arrow pointing towards the device at its Gate terminal which indicates the direction in which the current would flow, provided the pn junction is forward biased.
Working of n-channel JFETIn n-channel JFET, the majority charge carriers will be the electrons as the channel formed in-between the source and the drain is of n-type. Further, the working of these devices depends upon the voltages applied at its terminals (Figure 2).
Case I: Consider the case where no voltage is applied to the device i.e. VDS = 0 and VGS = 0. At this state, the device will be idle and no current flows through it i.e. IDS = 0. Case II: Now consider that the drain terminal of the device is connected to the positive terminal of the battery while its negative is connected to the source i.e. VDS = +ve. However let the gate terminal remain at unbiased state, which means VGS = 0. At this instant, the electrons within the n-substrate of the device start moving towards the drain being attracted by the positive force exerted by the battery. At the same time, the electron will also be repelled from the source as it is connected to the negative terminal of the voltage supply. This results in a net flow of current from drain to source (as per conventional direction) whose value is restricted only by the resistance offered to it by the channel. Further, it is seen that the increase in VDS increases the current flowing through the device at an initial state which can be termed to be JFET's Ohmic region. However, it is to be noted that the increase in VDS also causes an increase in the width of the depletion regions surrounding the pn junctions. This inturn causes the channel width to reduce, thereby increasing its resistance. This phenomenon continues till both of the depletion regions grow upto an extent wherein they almost seem to touch each other, a condition referred to as pinch-off. The corresponding value of VDS is referred to as pinch-off voltage, VP. Nevertheless, even in this case, a narrow channel with high current density exists within the device due to which IDS will get saturated to a level of IDSS as indicated in Figure 2. It is this behaviour of the JFET which causes it to behave as a constant current source. Case III: Next, for the set-up described in Case II, let us add the voltage source at the gate terminal such that the gate is negative w.r.t source i.e. VGS = -ve while VDS is +ve. In this case, the device behaves in a way very-similar to that in Case II, but for a lower value of VDS. This means that the pinch-off and the saturation occur quite earlier and are decided by the negative potential applied at the gate i.e. more negative the VGS, earlier the pinch-off due to which earlier will be the saturation, reducing IDSS (Figure 3). As the phenomenon continues, it is seen that a condition arises wherein the saturation level of the drain-to-source current I¬DS occurs right for a value of 0 mA. This means that there is no current flow through the device and essentially the device will turn OFF. The value of VDS for which this happens will be nothing but the negative pinch-off voltage i.e. VDS = -VP.