Equivalent Circuit for an Induction MotorPublished on 24/2/2012 & updated on 24/8/2018
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Where, Ns is synchronous speed of rotation which is given by- Where, f is the frequency of the supply voltage. P is the number of poles of the machine.
Equivalent CircuitThe equivalent circuit of any machine shows the various parameter of the machine such as its Ohmic losses and also other losses. The losses are modeled just by inductor and resistor. The copper losses are occurred in the windings so the winding resistance is taken into account. Also, the winding has inductance for which there is a voltage drop due to inductive reactance and also a term called power factor comes into the picture. There are two types of equivalent circuits in case of a three-phase induction motor-
Exact Equivalent CircuitHere, R1 is the winding resistance of the stator. X1 is the inductance of the stator winding. Rc is the core loss component. XM is the magnetizing reactance of the winding. R2/s is the power of the rotor, which includes output mechanical power and copper loss of rotor. If we draw the circuit with referred to the stator then the circuit will look like-
Here all the other parameters are same except- R2’ is the rotor winding resistance with referred to stator winding. X2’ is the rotor winding inductance with referred to stator winding. R2(1 - s) / s is the resistance which shows the power which is converted to mechanical power output or useful power. The power dissipated in that resistor is the useful power output or shaft power.
Approximate Equivalent CircuitThe approximate equivalent circuit is drawn just to simplify our calculation by deleting one node. The shunt branch is shifted towards the primary side. This has been done as the voltage drop between the stator resistance and inductance is less and there is not much difference between the supply voltage and the induced voltage. However, this is not appropriate due to following reasons-
- The magnetic circuit of induction motor has an air gap so exciting current is larger compared to transformer so exact equivalent circuit should be used.
- The rotor and stator inductance is larger in induction motor.
- In induction motor, we use distributed windings.
Power Relation of Equivalent Circuit
- Input power to stator- 3 V1I1Cos(Ɵ). Where, V1 is the stator voltage applied. I1 is the current drawn by the stator winding. Cos(Ɵ) is the stator power stator.
- Rotor input = Power input- Stator copper and iron losses.
- Rotor Copper loss = Slip × power input to the rotor.
- Developed Power = (1 - s) × Rotor input power.
Equivalent Circuit of a Single Phase Induction MotorThere is a difference between single phase and three phase equivalent circuits. The single phase induction motor circuit is given by double revolving field theory which states that- A stationary pulsating magnetic field might be resolved into two rotating fields, both having equal magnitude but opposite in direction. So the net torque induced is zero at standstill. Here, the forward rotation is called the rotation with slip s and the backward rotation is given with a slip of (2 - s). The equivalent circuit is- In most of the cases the core loss component r0 is neglected as this value is quite large and does not affect much in the calculation. Here, Zf shows the forward impedance and Zb shows the backward impedance. Also, the sum of forward and backward slip is 2 so in case of backward slip, it is replaced by (2 - s). R1 = Resistance of stator winding. X1 = Inductive reactance of the stator winding. Xm = Magnetising reactance. R2’ = Rotor Reactance with referred to stator. X2’ = Rotor inductive reactance with referred to stator.
Calculation of Power of Equivalent Circuit
- Find Zf and Zb.
- Find stator current which is given by Stator voltage/Total circuit impedance.
- Then find the input power which is given by Stator voltage × Stator current × Cos(Ɵ) Where, Ɵ is the angle between the stator current and voltage.
- Power Developed (Pg) is the difference between forward field power and backward power. The forward and backward power is given by the power dissipated in the respective resistors.
- The rotor copper loss is given by- slip × Pg.
- Output Power is given by- Pg - s × Pg - Rotational loss. The rotational losses include friction loss, windage loss, Core loss.
- Efficiency can also be calculated by diving output power by input power.
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