# Electric Field Strength or Electric Field Intensity

**Electric field strength**or

**electric field intensity**is the synonym of electric field.

**Electric field strength**can be determined by Coulomb’s law. According to this law, the force ‘F’ between two point charges leaving charge Q

_{1}and Q

_{2}and placed at a distance d from each other is given by, Where, K is any constant, in SI system the force between two charges is given by Here, ε

_{o}is the permittivity of vacuum = 8.854 x 10

^{ − 12}F/m and ε

_{r}is the relative permittivity of the surrounding medium.

Now if Q_{2} = + 1 Coulomb, then
This equation shows the force acting the a unit positive charge placed at a distance d from charge Q_{1}.
As per definition this is nothing but of electric field strength of charge Q_{1} at a distance d from that charge. This field strength can also be written as,
Depending on this expression, the electric field strength can be expressed in Newton/Coulomb and it can also be expressed as Volt/Meter (volts per meter). [ This can be proved that these two unit are equivalent.] The electric field strength has direction and hence it is vector quantity.
Intensity means the magnitude or amount. Now field intensity similarly means the magnitude of the strength of the field. Finally electric field intensity or strength can be written as,

### Video on Electric Field

**electric flux**around it, this field though theoretically assumed to be spread up to infinity but practically they are taken to be composed of small closed space.

**Now from each point of charged surface, electric field tube force emerges, which radiates through the surrounding. This total number of force tube is called**The field is nothing but an energy field, i.e. to go through the field work is done by or done upon a point charge. So, there must be some kind of energy present in the electric field.

**electric flux**.### Electric Field Due to a Point Charge

If we consider a point charge of Q Coulomb, the total number of flux radiating from the charge (Q Coulombs) is equal to Q coulombs.## Electric Flux Density

The tube forces which are termed as electric flux, radiate normally from the entire surface enclosing a point charge is nothing but the total charge of the point. Now, the amount of radiating this flux through unit surface area on the imaginary enclosure of the charge, is known as**electric flux density**. The unit of this is coulombs/m

^{2}.

Let's take a point charge of Q coulomb and place it at the center of a sphere of radius ’r’ then the electric flux density is From the above relation we can see that the electric flux density does not depend on the medium, i.e. the absolute permittivity and relative permittivity, and it is inversely proportional with the square of the distance from the charge.

We know that electric field intensity or electric field strength is given as Hence, the relation between electric field intensity and electric flux density is given by the equation

#### Electric Dipole Moment

Electric dipole is created by two opposite and equal charges, a certain distance apart. It is equal to the product of one charge and the distance between them. Say two charges + Q and – Q apart from each other by a distance a. Then as per definition, electric dipole moment, This is a vector quantity directed from negative to positive charge.### Electric dipole in Electric Field

When an electric dipole is placed inside a uniform electric field, the negative end of the dipole is attracted by positive end of the field and positive end of the dipole is attracted by negative end of the field. Due to these two forces, which are opposite in direction, there would be a torque acting on the dipole body. Let this torque is τ and θ is the angle between electric dipole and electric field. The amplitude of force acting on charge Q in the electric field E is given as EQ. Due to this field the dipole will be oriented parallel to the electric field. Now let us calculate how much work to be done for this parallel orientation of dipole along the field. If due to this electric dipole moment, the orientation of dipole changes from θ_{1}to θ

_{2}. So work done for this angular moment is given as, This is the work done by electric field which will be stored as potential energy in the dipole. If dipole is aligned from its vertical position to parallel position with respect to direction of electric field. The Work done or potential energy stored is