# Switching Algebra or Boolean Algebra

on 24/2/2012 & Updated on 25/8/2018**Boolean algebra or switching algebra**is a system of mathematical logic to perform different mathematical operations in binary system. These are only two elements 1 and 0 by which all the mathematical operations are to be performed. There only three basis binary operations, AND, OR and NOT by which all simple as well as complex binary mathematical operations are to be done. There are many rules in Boolean algebra by which those mathematical operations are done. In Boolean algebra, the variables are represented by English Capital Letter like A, B, C etc and the value of each variable can be either 1 or 0, nothing else.

Some basic logical Boolean operations- AND operation, OR operation, Not operation,

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Some basic laws for Boolean Algebra, A . 0 = 0 where A can be either 0 or 1. A . 1 = A where A can be either 0 or 1. A . A = A where A can be either 0 or 1. A . Ā = 0 where A can be either 0 or 1. A + 0 = A where A can be either 0 or 1. A + 1 = 1 where A can be either 0 or 1. A + Ā = 1 A + A = A A + B = B + A where A and B can be either 0 or 1. A . B = B . A where A and B can be either 0 or 1. The laws of Boolean algebra are also true for more than two variables like,

### Cumulative Laws for Boolean Algebra

### Associative Laws for Boolean Algebra

### Distributive Laws for Boolean Algebra

### Redundant Literal Rule

From truth table,Inputs | Output | ||

A | B | ĀB | A + ĀB |

0 | 0 | 0 | 0 |

0 | 1 | 1 | 1 |

1 | 0 | 0 | 1 |

1 | 1 | 0 | 1 |

Inputs | Output | |

A | B | A+B |

0 | 0 | 0 |

0 | 1 | 1 |

1 | 0 | 1 |

1 | 1 | 1 |

### Absorption Laws for Boolean Algebra

Proof from truth table,Inputs | Output | ||

A | B | AB | A+A.B |

0 | 0 | 0 | 0 |

0 | 1 | 0 | 0 |

1 | 0 | 0 | 1 |

1 | 1 | 1 | 1 |

A | B | A+B | A.X(A+B) |

0 | 0 | 0 | 0 |

0 | 1 | 1 | 0 |

1 | 0 | 1 | 1 |

1 | 1 | 1 | 1 |

## Examples of Boolean Algebra

These are another method of simplifying complex Boolean expression. In this method we only use three simple steps.- Complement entire Boolean expression.
- Change all ORs to ANDs and all ANDs to ORs.
- Now, complement each of the variable and get final expression.

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