# No Load Test of Induction Motor

Published on 24/2/2012 and last updated on 25/8/2018This test gives the information regarding no-load losses such as core loss, friction loss and windage loss. Rotor copper loss at no load is very less that its value is negligible. Small current is required to produce adequate torque. This test is also well-known as running light test. This test is used to evaluate the resistance and impedance of the magnetizing path of induction motor.

## Theory of No Load Test of Induction Motor

The impedance of magnetizing path of induction motor is large enough to obstruct flow of current. Therefore, small current is applied to the machine due to which there is a fall in the stator-impedance value and rated voltage is applied across the magnetizing branch. But the drop in stator-impedance value and power dissipated due to stator resistance are very small in comparison to applied voltage. Therefore, there values are neglected and it is assumed that total power drawn is converted into core loss. The air gap in magnetizing branch in an induction motor slowly increases the exciting current and the no load stator I^{2}R loss can be recognized.

One should keep in mind that current should not exceed its rated value otherwise rotor accelerates beyond its limit.
The test is performed at poly-phase voltages and rated frequency applied to the stator terminals. When motor runs for some times and bearings get lubricated fully, at that time readings of applied voltage, input current and input power are taken. To calculate the rotational loss, subtract the stator I^{2}R losses from the input power.

## Calculation of No Load Test of Induction Motor

Let the total input power supplied to induction motor be W_{0}watts. Where, V

_{1}= line voltage I

_{0}= No load input current

Rotational loss = W

_{0}– S

_{1}Where, S

_{1}= stator winding loss = N

_{ph}I

^{2}R

_{1}N

_{ph}= Number phase The various losses like windage loss, core loss, and rotational loss are fixed losses which can be calculated by

Stator winding loss = 3I

_{o}

^{2}R

_{1}Where, I

_{0}= No load input current R

_{1}= Resistance of the motor

Core loss = 3G

_{o}V

^{2}

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