Discharging a Capacitor
Let us connect a charged capacitor of capacitance C farad in series with a resistor of resistance R ohms. We then short circuit this series combination through switching on the push switch as shown. As soon as the capacitor is short circuited, it starts discharging.
Let us assume, the voltage of the capacitor at fully charged condition is V volt. As soon as the capacitor is short circuited, the discharging current of the circuit would be, - V / R ampere. But after the instant switching on that is after t = 0 the current through the circuit is As per Kirchhoff’s’ Voltage Law, we get, Integrating both sides, we get, Where, A is the constant of integral and, at t = 0, v = V, After, calculating value of A, we get, We know form, KVL of the circuit, If we plot these discharging current and voltage in raph, we get,