# Superposition Theorem

Published on 24/2/2012 & updated on 9/8/2018HOME / CIRCUIT THEORY / CIRCUIT THEOREM

Here, two 1.5 Volt batteries present in the circuit. At this condition, the current through 1 ohm resistance is 1.2 ampere. The ammeter indicates this value in the above picture.

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Now, we replace the left side battery by a short circuit as shown. In this case the current flowing through the 1 ohm resistance is 0.6 ampere. The ammeter indicates this value as shown in the picture above.

Now, we replace the right side battery by a short circuit as shown. In this case the current flowing through the 1 ohm resistance is also 0.6 ampere. The ammeter indicates this value as shown in the picture above.
1.2 = 0.6 + 0.6
So, we can say, if we connect a branch of an electrical circuit with numbers of voltage and current sources total current flowing through this branch is the summation of all individual currents, contributed by the each individual voltage or current source. This simple conception is mathematically represented as **Superposition Theorem**.

Instead of having two sources as shown above, there are n number of sources acting in a circuit due to which I current flows through a particular branch of the circuit.
If someone replaces all the sources from the circuit by their internal resistance except first source which is now acting along in the circuit and giving current I_{1} through the said branch, then he reconnects the second source and replaces the first source by its internal resistance.
Now the current through that said branch for this second source alone can be assumed I_{2}.
Similarly, if he reconnects the third source and replaces the second source by its internal resistance. Now the current through that said branch for this third source, alone is assumed I_{3}.
Similarly, when n^{th} source acts alone in the circuit and all other sources are replaced by their internal electrical resistances, then said I_{n} current flows through the said branch of the circuit.
Now according to **Superposition theorem**, current through the branch when all the sources are acting on the circuit simultaneously, is nothing but summation of these individual current caused by individual sources acting alone on the circuit.
Electrical sources may be of two kinds mainly, one is voltage source and other is current source. When we remove the voltage source from a circuit, the voltage, was contributed to the circuit becomes zero. So for getting zero electric potential difference between the points where the removed voltage source was connected, these two points must be short circuited by zero resistance path. For more accuracy, one can replace the voltage source by its internal resistance. Now if we remove a current source from the circuit, current is contributed by this source will become zero. Zero current implies open circuit. So when we remove current source from a circuit, we just disconnect the source from the circuit terminals and keep both terminals open circuited. As the ideal internal resistance of a current source is infinitely large, removing a current source from a circuit can be alternatively referred as replacing the current source by its internal resistance. So for superposition theorem, the voltage sources are replaced by short circuits and source s are replaced by open circuits.

This theorem is only applicable to linear circuit i.e. circuit consisting of resistances in which Ohm’s law is valid. In the circuits having non-linear resistances such as thermionic valves, metallic rectifiers this theorem will not be applicable. This theorem is a more laborious one than many other circuit theorems. But main advantage of this method is that, it avoids solutions of two or more simultaneous equations. But after a little practice with this method, equations can be written directly from the original circuit diagram and labor in drawing extra diagrams can be saved. For better understanding of the procedure, we have furnished the different steps of **Superposition theorem** as follows,

Step - 1
Replace all but one of the sources by their internal resistances.

Step - 2
Determine the currents in various branches using simple Ohm’s law.

Step - 3
Repeat the process using each of the sources turn - by turn as the sole source each time.

Step - 4
Add all the currents in a particular branch due to each source. This is the desired value of current at that branch when all the sources acting on the circuit simultaneously.

#### Example of Superposition Theorem

Suppose there are two voltage sources V_{1}and V

_{2}acting simultaneously on the circuit. Because of these two voltage sources, say current I flows through the resistance R. Now replace V

_{2}by short circuit, keeping V

_{1}at its position and measure current through the resistance, R. Say it is I

_{1}. Then replace, V

_{1}by short circuit, reconnect V

_{2}to its original position and measure current through the same resistance R and say it is I

_{2}. Now if we add these two currents, I

_{1}and I

_{2}we will get the current which is equal to the current - was actually flowing through R, when both voltage sources V

_{1}and V

_{2}were acting on the circuit simultaneously. That is I

_{1}+ I

_{2}= I.

### Video Presentation of an Example of Superposition Theorem

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