# Sag in Overhead Conductor

Published on 24/2/2012 & updated on Saturday 28th of April 2018 at 04:24:32 PMHOME / TRANSMISSION / PERFORMANCE OF TRANSMISSION LINE

## What is Sag?

**is defined as the different in level between points of supports and the lowest point on the conductor. Here AOB is the transmission line conductor. Two supports are at point A and at point B. AB is the horizontal line and from this horizontal line to point O, S is the sag when measured vertically.**

*Sag*## Why Sag Provision is Mandatory in Transmission Line Conductors?

Sag is mandatory in transmission line conductor suspension. The conductors are attached between two supports with perfect value of sag. It is because of providing safety of the conductor from not to be subjected to excessive tension. In order to permit safe tension in the conductor, conductors are not fully stretched; rather they are allowed to have sag. If the conductor is stretched fully during installation, wind exerts pressure on the conductor, hence conductor gets chance to be broken or detached from its end support. Thus**sag**is allowed to have during conductor suspension. Some important points are to be mentioned:

- When same leveled two supports hold the conductor, bend shape arises in the conductor. Sag is very small with respect to the span of the conductor.
- Sag span curve is like parabolic.
- The tension in each point of the conductor acts always tangentially.
- Again the horizontal component of the tension of conductor is constant throughout conductor length.
- The tension at supports is nearly equal to the tension at any point of the conductor.

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## How to Calculate Sag?

Sag calculation is classified on two conditions.- When supports are at equal levels
- When supports are not at equal levels

Sag calculation for supports are at equal levels Suppose, AOB is the conductor. A and B are points of supports. Point O is the lowest point and the midpoint. Let, L = length of the span, i.e. AB w is the weight per unit length of the conductor T is the tension in the conductor. We have chosen any point on conductor, say point P. The distance of point P from Lowest point O is x. y is the height from point O to point P.

Equating two moments of two forces about point O as per the figure above we get,
Sag calculation for supports are at unequal levels
Suppose AOB is the conductor that has point O as the lowest point.
L is the Span of the conductor.
h is the difference in height level between two supports.
x_{1} is the distance of support at the lower level point A from O.
x_{2}is the distance of support at the upper level point B from O.
T is the tension of the conductor.
w is the weight per unit length of the conductor.
Now,
So, having calculated the value of x_{1} and x_{2}, we can easily find out the value of sag S_{1} and sag S_{2}.
The above formula are used to calculate sag when the conductor is in still air and ambient temperature is normal. Hence the weight of the conductor is its own weight.

## What is the Effect of Ice and Wind on Sag?

- The weight per unit length of the conductor is changed when wind blows at a certain force on the conductor and ice accumulate around the conductor.
- Wind force acts on the conductor to change the conductor self weight per unit length horizontally in the direction of the air flow.
- Ice loading acts on the conductor to change the conductor self weight per unit length vertically downward.
- Considering wind force and ice loading both at a time, the conductor will have a resultant weight per unit length.
- The resultant weight will create an angle with the ice loading down ward direction.

_{i}is the weight of ice per unit length w

_{i}= density of ice × volume of ice per unit length w

_{w}is the force of wind per unit length w

_{w}= wind pressure per unit area × projected area per unit length So, the total weight of the conductor per unit length is The sag in the conductor is given by So the vertical sag

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