# Inductance of Two Wire Single Phase Transmission Line

on 24/2/2012 & Updated on Tuesday 1st of May 2018 at 12:22:07 PM_{A}carries a current of I

_{A}in opposite direction of current I

_{B}through the conductor B of radius r

_{B}. Conductor A is at a distance D from conductor B and both are of length l. They are in close vicinity with each other so that flux linkage takes place in both of the conductors due to their electromagnetic effects.

Let us consider the magnitude of current in both conductors are same and hence I_{A} = - I_{B},
Now, total flux linkage in conductor A = flux linkage by self-current of conductor A + flux linkage on conductor A due to current in the conductor B.
Similarly, flux linkage in conductor B = flux linkage by self-current of conductor B + flux linkage on conductor B due to current through conductor A.
Now if we consider a point P in close vicinity both conductor A and B, the flux linkage at point P would be, flux linkage at point P for current carrying conductor A + flux linkage at point P for current carrying conductor B i.e.

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Now, ……… shown in the figure below in figure (a) and (b).

- λ
_{AAP}is the flux linkage at point P for conductor A due to current through conductor A itself. - λ
_{ABP}is the flux linkage at point P for conductor A due to current through conductor B. - λ
_{BAP}is the flux linkage at point P for conductor B due to current through conductor A. - λ
_{BBP}is the flux linkage at point P for conductor B due to current through conductor B itself.

λ_{ABP} and λ_{BAP} are negative in value because the directions current are opposite with respect to each other.

If we consider that both conductor are with same radius, i.e. r_{A} = r_{B} = r and point P is shifted to infinite distance then we can write that
If conductor A becomes bundled conductor, then its geometrical mean radius (GMR) will be calculated for n number of conductors per bundle.
Where, d is the distance between the central axis of conductors within the bundle.

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