01․ Find H for centre of solenoid having finite length d = 1 unit where N = no of turns = 500, I = 2 A.

From Biot Savarts law, magnetic field intensity for a solenoid is given as
H = NI/u

_{x}.02․ A magnetic vector potential is given by the expression

**A**= (- cos x) (cos y) u_{z}. The flux density at the origin isB = curl of A
Since flux density at origin (x = 0, y = 0) so B = 0.

03․ A circular loop has its radius increasing at a rate of 2 m/s. The loop placed perpendicular to a constant magnetic field of 0.5 wb/m

^{2}. When the radius of the loop is 4 m. the emf induced in the will beArea of the loop A = π r

^{2}Magnetic of unit emf induced dQ/dt.04․ A magnetic field B = 5 × 10

^{-2}u_{z}T exerts a force on 0.02 m conductor along the x-axis. The conductor carried a current of 5 mA in the – u_{x}direction. What force must be applied to the conductor to hold it in positionF = IL × B
Applied forced F

_{a}= - (IL × B) Since F_{a}force hold conductor position. So the force will be opposed.05․ The hysteresis loop of a magnetic material has an area of 5 cm

^{2}with the scale given as 1 cm = 2 AT and 1 cm = 50 mwb At 50 Hz; the total hysteresis loss isPower loss in watt given as,
P

_{h}= W_{h}v.f Where W_{h}= energy density loss V = Volume of material In this case, W_{h}.V = area of hysteresis loop = 5 cm^{2}.06․ A wire 1 m long carries a current of 5A and is at an angle of 30

^{o}with B = 1.5 wb/m^{2}. Magnitude of force isF = BIL sinθ.

07․ A negative point charge q = - 40 nC is moving with velocity of 6 × 10

^{6}m/s in a direction specited by unit vector u_{y}+ 0.6 u_{z}. Find the magnitude of force vector on the moving particle by the field**B**= 2 u_{x}+ 3 u_{y}+ 5 u_{z}mT and**E**= 2 u_{x}- 3 u_{y}+ 5 u_{z}KV/mApply F = Q(E + V × B).

08․ The Kirchhoff’s current law is implict in expression

Current at a node is zero, current entering = current leaving. So, surface integral of (j.ds) = 0.

09․ The magnetic field at any point on the axis of current carrying circular coil will be

With coil x – y plane, the field will be in u

_{z}direction.10․ A coil of 300 turns is wound on a non magnetic core having a mean circumference of 300 mm and a cross sectional area of 300 mm

^{2}. The inductance of the coil corresponding to a magnetizing current of 6 A will beInductance of coil,

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