01․ The synchronous motor can be started by
02․ Under which of the following conditions hunting of synchronous motor is likely to occur ?
03․ A 500 V, 120 KW, 50 Hz, star connected synchronous motor operating at 0.8 power factor leading has full load efficiency of 91%. The armature resistance is equal to 0.08Ω. The magnitude of armature current is nearly equal to
Thw input power is Pin = Pout / φ· = 120 KW/0.91 = 131.86 KW. Armature current is given by,
04․ For a practical synchronous motor the pull out torque will occur when the torque angle is nearly equal to
The maximum torque i.e. pull out torque will occur at θ = 90°. But this is possible for the motor having smooth rotors. As most practical motors have salient poles, so the pull out torque occurs at a torque angle about to 75°.
05․ If the mechanical angle ÃŽÂ± between the stator and rotor poles increases, then the stator current
At no load the axis of stator and rotor poles concide. As the motor is loaded the rotor poles falls slightly behind the stator poles, while running at synchronous speed. The increased power is drawn from AC source (Stator Winding). Thus the stator current increases.
06․ In the V curve shown in figure below for a synchronous motor, the parameter of Y and X coordinates are, respectively
When the magnitude of the armature current is plotted as a function of the excitation current for various load conditions, we obtain a set of nested curves, so called V curves.
07․ In synchronous generator a synchronous dead load (lamp, furnaces etc) has no ____________ hence it has no natural frequency of oscillation.
08․ In diesel engine, gas engine type of machine contains ___________________ pole type of alternator.
09․ What is the frequency of a alternator, if P = number of poles and N = revolution made per second?
If a two poles alternator rotates one complete rotation, it produces one cycle of generated voltage. If a P poles alternator rotates one complete rotation, it produces P/2 cycles of generated voltage. If a P poles alternator rotates N complete rotations, it produces NP/2 cycles of generated voltage. As the N is the rotation made per second, the frequency that is number of cycles produced during one second, of the generated voltage would be NP/2 Hz.
10․ In alternator, the rotary part is
Basically, the alternators have the field winding in its rotary part and the armature windings in its stationary part. We know that the field winding produces the magnetic fields and the other name of the field winding is magnetic field poles. Hence, the rotary part of the alternator is magnetic field poles.