01․ The decimal equivalent of hexadecimal number of 2A0F is

02․ The binary equivalent of hexadecimal number 4F2D is
4→0100
F→1111
2→0010
D→1101
Hence, (4F2D)16 = (0100 1111 0010 1101)2
03․ To get an excess-3 code from BCD code
As name implies in excess-3 representation excess number is 3. So to get excess-3 code from BCD code we have to add 0011.
04․ Consider the following multiplication:
(10w1z) × (15)10 = (y01011001)2
Which one of the following gives appropriate values of w,y and z?

05․ Which of the following notations have two representations of zero?
(I) 1’s complement with radix of number being 2
(II) 7’s complement with radix of number being 8
(III) 9’s complement with radix of number being 10
(IV) 10’s complement with radix of number being 10
Select the correct answer using the codes given below:
Odd’s complement like 1’s,7’s,9’s have two representation of zero.
06․ AND operation of (79)10 & (-56)10 is

07․ Statement(A): 2’s complement arithmetic is preferred in digital computers.
Statement(R):The Hardware required to obtain the 2’s complement of a number is simple.
All modern computers operates based on 2’s complement as hardware is faster and simpler.
08․ A new Binary Coded Pantry (BCP) number system is proposed in which every digit of a base-5 number is represented by its corresponding 3-bit binary code. For example, the base-5 number 24 will be represented by its BCP code 010100. In this numbering system,the BCP code 100010011001 corresponds to the following number in base-5 system

09․ Which one of the following is an invalid state in 8-4-2-1 binary coded decimal counter
1100(>9) is the invalid BCD representation.
10․ The number of 1 in 8-bit representation of 127 in 2’s complement form is m and that in 1,s complement form is n. What is the value of m:n?
127→01111111
1’s complement → 10000000(n)
2’s complement → 10000001(m)
Hence, m:n = 2:1
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