01․ For emitter bias, the voltage at the emitter is 0.7 V less than the

In the emitter bias, the base-emitter terminal is connected with the base resistor. So, according to the KVL, the total base voltage is the summation of the voltage drop across the base resistance and the base emitter voltage. Hence, the base emitter voltage is always less than the base voltage.

02․ Given (135)

_{x}+ (144)_{x}= (323)_{x}what is the value of base x?(135)

_{x}+ (144)_{x}= (323)_{x}(X^{2}+ 3X + 5) + (X^{2}+ 4X + 4) = (3X^{2}+ 2X + 3) X^{2}- 5X-6 = 0 X = 6 - 1 As value of base can’t be negative so x = 6.03․ If (211)

_{X}= (152)_{8}, then the value of base x is2x

^{2}+x+1 = 64 + 5 * 8 + 2 By solving we get X=7